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Home/ Questions/Q 7817575
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T06:16:17+00:00 2026-06-02T06:16:17+00:00

I was under impression that .replace and -replace were the exact same thing, however

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I was under impression that .replace and -replace were the exact same thing, however I found that I could not accomplish some RegEx tasks with .replace that I could with -replace. Could someone please point out what I’m missing?

Broken Regex replace:
$a=$a.Replace('.:\\LOGROOT\\', "\\$env:computername\logroot\")


Working Regex replace:
$a=$a -Replace('.:\\LOGROOT\\', "\\$env:computername\logroot\")

ps:
The following URL leads me to think there are .replace options I am unfamiliar with, but I cant seem to find any additional information on how to use them, or how to access the help for these options. http://www.computerperformance.co.uk/powershell/powershell_regex.htm
Regex.Replace(String, String, String, RegexOptions) and also:
Regex.Replace(String, String, MatchEvaluator, RegexOptions) methods.

Thank you

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  1. Editorial Team
    Editorial Team
    2026-06-02T06:16:18+00:00Added an answer on June 2, 2026 at 6:16 am

    While @Keith Hill’s answer explains the difference between Replace method and the -replace operator, to explain why you might not see the same result, it is because you are using the String.Replace method which does string replace and -replace operator uses regex replace. You can use the Regex.Replace method for this purpose and you should see the same effect:

    [regex]::replace($a,'.:\\LOGROOT\\', "\\$env:computername\logroot\")
    

    In short, the -replace operator is same as Regex.Replace (the particular overload linked above), but in general Replace() can be instance or static method that can be doing anything completely different from -replace

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