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Editorial Team
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Asked: 2026-05-19T22:36:18+00:00

I was using JQuery’s $.getJSON to retrieve a list of tweets and for an

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I was using JQuery’s $.getJSON to retrieve a list of tweets and for an unknown reason some of the tweet id(s) were being rounded
"id": 34903960418516968, to "id": 34903960418516970,
So instead I tried using $.ajax with dataType: “text”, and then did the conversion to JSON via parseJSON, JSON.parse and eval which did not work.
The only solution that I found was to make the datatype of the ID String instead of Number while the JSON source is still in text format. I surrounded the actual ID with double quotes ” and I used the following regular expression to do that.

data = data.replace(/\"id\": (\d{15,}),/gi, "\"id\": \"$1\",");

ajax call 

$.ajax({
         async: true,
         url: tweetsUrl,
         dataType: "text",
         success: getTweetsResult
       });

the getTweetsResult 

function getTweetsResult(data, textStatus, xhr){
    //remove trailing ,
    data = data.substring(0, data.lastIndexOf(",]")) + "]";
    //convert tweet.id to string because the eval of JS is rounding up some of the number
    data = data.replace(/\"id\": (\d{15,}),/gi, "\"id\": \"$1\",");
    //console works with Chrome
    //  console.log(data);
    var tweetList = $.parseJSON(data);
    generateTweets("tweets", "tweetGrid", tweetList, 3, tweets);
    applyRollOverGridItems();
}
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1 Answer

  1. Editorial Team

    I remember reading on the twitter blog that the twitter ID data type had changed and that developers had to update their code. If I remember correctly, they now send the ID as a string variable as well as a long (or float, not sure which) variable. Have a look at the response, and get the ID from the string variable. Should solve that issue.

    EDIT: Found the URLS

    http://groups.google.com/group/twitter-development-talk/browse_thread/thread/6a16efa375532182?pli=1

    http://blog.programmableweb.com/2010/10/19/the-twitter-id-shuffle-text-vs-numbers/

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