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Editorial Team
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Asked: 2026-05-15T03:47:12+00:00

I was using Sonar to make my code cleaner, and it pointed out that

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I was using Sonar to make my code cleaner, and it pointed out that I’m using new Integer(1) instead of Integer.valueOf(1). Because it seems that valueOf does not instantiate a new object so is more memory-friendly. How can valueOf not instantiate a new object? How does it work? Is this true for all integers?

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1 Answer

  1. Editorial Team

    Integer.valueOf implements a cache for the values -128 to +127. See the last paragraph of the Java Language Specification, section 5.1.7, which explains the requirements for boxing (usually implemented in terms of the .valueOf methods).

    http://docs.oracle.com/javase/specs/jls/se7/html/jls-5.html#jls-5.1.7

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