Question

I was wondering about the logic in this function declaration:

CMyException (const std::string & Libelle = std::string(),...

What is the point of using a variable by reference? Usually you pass a variable by reference whenever it may be modified inside… so if you use the keyword const this means it’ll never be modified.

This is contradictory.

May someone explain this to me?

Answer 1

Actually reference is used to avoid unnecessary copy of the object.

Now, to understand why const is used, try this:

std::string & x= std::string(); //error

It will give compilation error. It is because the expression std::string() creates a temporary object which cannot be bound to non-const reference. However, a temporary can be bound to const reference, that is why const is needed:

const std::string & x = std::string(); //ok

Now coming back to the constructor in your code:

CMyException (const std::string & Libelle = std::string());

It sets a default value for the parameter. The default value is created out of a temporary object. Hence you need const (if you use reference).

There is also an advantage in using const reference : if you’ve such a constructor, then you can raise exception like this:

throw CMyException("error"); 

It creates a temporary object of type std::string out of the string literal "error", and that temporary is bound to the const reference.