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Home/ Questions/Q 8936575
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T10:14:35+00:00 2026-06-15T10:14:35+00:00

I was wondering how static worked. Here is an example: void count() { static

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I was wondering how static worked. Here is an example:

void count()
{
    static int x = 1;
    cout << "Static: " << x << endl;
    x++;

    return;
}

int main()
{
    //Static variable test
    cout << endl;
    count();
    count();
}

This program gives an output of “1 and 2”. But I was wondering when the function “count” is called for the second time, why isn’t the “static int x = 1” line executed?

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  1. Editorial Team
    Editorial Team
    2026-06-15T10:14:36+00:00Added an answer on June 15, 2026 at 10:14 am

    This is a language rule; the initialization of a static variable is only performed once.

    Note that this is different from

    static int x;
    x = 1;
    

    which would reset x to 1 in every call.

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