Question

I was wondering how would go about displaying five images in a row using lists. For example, how would I generate the following XHTML code below using PHP & MySQL?

Here is the XHTML code.

<ul>
    <li><a href="#" title=""><img src="" /></a></li>
    <li><a href="#" title=""><img src="" /></a></li>
    <li><a href="#" title=""><img src="" /></a></li>
    <li><a href="#" title=""><img src="" /></a></li>
    <li><a href="#" title=""><img src="" /></a></li>
</ul>

<ul>
    <li><a href="#" title=""><img src="" /></a></li>
    <li><a href="#" title=""><img src="" /></a></li>
    <li><a href="#" title=""><img src="" /></a></li>
    <li><a href="#" title=""><img src="" /></a></li>
    <li><a href="#" title=""><img src="" /></a></li>
</ul>

Here is my PHP & MySQL code so far.

$url = array();
$title = array();

$dbc = mysqli_query($mysqli,"SELECT *
                             FROM images
                             GROUP BY images.id");

if (!$dbc) {
    print mysqli_error($mysqli);
} else {
    while($row = mysqli_fetch_array($dbc)){ 
        $url[] = $row["url"];
        $title[] = $row["title"];
    }
}

Answer 1

just echo it out it your while loop:
EDIT: noticed your example has a new ul every 5 images, code has been adjusted to handle that.

if (!$dbc) {
    print mysqli_error($mysqli);
} else {
    $rowCount = 0;
    while($row = mysqli_fetch_array($dbc)){ 
        if($rowCount % 5 == 0){
         echo "<ul>";
        }
       echo "<li><a href='" .$row["url"]. "' title='".$row['title']."'>";
        echo "<img src='".$row['src']."'></a></li>";
       if($rowCount % 5 == 4) {
         echo "</ul>";
       }
       $rowCount++;
    }

}