Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I was wondering, I know that $(selector) returns a jQuery object, but say I have a series of div in the body such as:
<body>
<div> </div>
<div> </div>
<div> </div>
</body>
When I try $(“div”), jQuery should return a jQuery object that is like an array of divs, BUT when I try to specify a certain div like $(“div”)[1], is this not a jQuery object? And if it isn’t, I know I can’t use .css() so how can I change the css of a specific div that I need to be determined dynamically?
$("div")returns an array of DOM elements.$("div")[1]gets the 2nd element on the page, as a DOM element. To make it back into a jQuery object, you can do$($("div")[1]).I don’t suggest you do that though. You can use the
:eq()selector to get the div you want.Or, you can use the
.eq()function.