Question

I was wondering if anyone could help with a query to select part of a column.

The column ‘criteriadata’ contains data that would look like this:

CriteriaData

14 27 15 C

14 30 15 DD

14 38 15 Pass

14 33 15 Pass

How can I select just the data that appears after the number 15.

Many thanks.

Answer 1

SELECT RIGHT(CriteriaData, 
             LEN(CriteriaData) - CHARINDEX('15', CriteriaData, 1) - 2)
FROM TableName
WHERE CriteriaData LIKE '%15%';

SQL Fiddle Demo