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Home/ Questions/Q 8884625
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T21:06:22+00:00 2026-06-14T21:06:22+00:00

I was wondering if (in C++) you can instantiate a class (class foo) then

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I was wondering if (in C++) you can instantiate a class (class foo) then have said class return the already instantiated object. (foo::instance())

In other words, can I have a class return it’s-self via it’s own methods? I want to be able to create a class (i.e. class foo) early in my program so it is already setup and ready to go. Then, farther down the line, I want to be able to call functions from that class without having to pass that object as an argument to my calling function. Can I do something like so:
MyClass::ReturnSelf()->foo();
or
MyClass::ReturnSelf().foo();

EDIT: I just realized this might be a little unclear. I want to be able to have another class call this “self-returning” method so it can use the already instantiated object’s methods and members without creating a new object.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T21:06:23+00:00Added an answer on June 14, 2026 at 9:06 pm

    Congrats, you’ve discovered the singleton pattern. Quite a caveat, if you didn’t already know it.

    struct X
    {
       static X& instance()
       {
           static X x;
           return x;
       }
    
       void foo();
    };
    

    and call the method as:

    X::instance().foo();
    

    Of course, you could also make the method static, if that’s an option, and call it directly:

    X::foo(); //this requires foo to be declared static
    

    The effect of returning the instance from methods can also be used for method chaining:

    struct Element
    {
        Element& setColor() { return *this; }
        Element& setWidth() { return *this; }
    };
    
    Element e;
    e.setColor().setWidth();
    
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