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Asked: May 10, 20262026-05-10T19:47:30+00:00 2026-05-10T19:47:30+00:00

I was wondering if in Java I would get any odd behaviour if I

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I was wondering if in Java I would get any odd behaviour if I synchronise twice on the same object?

The scenario is as follows

pulbic class SillyClassName {      object moo;     ...     public void method1(){         synchronized(moo)         {             ....             method2();             ....         }     }      public void method2(){         synchronized(moo)         {             doStuff();         }     } } 

Both methods use the object and are synchronised on it. Will the second method when called by the first method stop because it’s locked?

I don’t think so because it’s the same thread but I’m unsure of any other odd results that might occur.

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  1. 2026-05-10T19:47:31+00:00Added an answer on May 10, 2026 at 7:47 pm

    Reentrant

    Synchronized blocks use reentrant locks, which means if the thread already holds the lock, it can re-aquire it without problems. Therefore your code will work as you expect.

    See the bottom of the Java Tutorial page Intrinsic Locks and Synchronization.

    To quote as of 2015-01…

    Reentrant Synchronization

    Recall that a thread cannot acquire a lock owned by another thread. But a thread can acquire a lock that it already owns. Allowing a thread to acquire the same lock more than once enables reentrant synchronization. This describes a situation where synchronized code, directly or indirectly, invokes a method that also contains synchronized code, and both sets of code use the same lock. Without reentrant synchronization, synchronized code would have to take many additional precautions to avoid having a thread cause itself to block.

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