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Home/ Questions/Q 85871
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Asked: May 10, 20262026-05-10T22:09:26+00:00 2026-05-10T22:09:26+00:00

I was wondering if it is possible to declare an array (size not known

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I was wondering if it is possible to declare an array (size not known at this time), as a private member of a class and later set the size in the constructor of the class. For example:

class Test { int a[]; public: Test(int size); };  Test::Test(int size) { a[size];   // this is wrong, but what can i do here? } 

Is this possible or should I use dynamic arrays? Thanks!

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  1. 2026-05-10T22:09:27+00:00Added an answer on May 10, 2026 at 10:09 pm

    No this is not possible. Array declarations in headers must have constant sized value. Otherwise it’s impossible for constructs like ‘sizeof’ to function properly. You’ll need to declare the array as a pointer type and use new[] in the constructor. Example.

    class Test {      int *a; public:     Test(int size) {        a = new int[size];     }     ~Test() { delete [] a; } private:     Test(const Test& other);     Test& operator=(const Test& other); }; 
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