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Home/ Questions/Q 7813759
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T04:58:42+00:00 2026-06-02T04:58:42+00:00

I was wondering if someone could help me with a small problem I’m having.

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I was wondering if someone could help me with a small problem I’m having.

I am trying to print out an array of 100 items, every row needs 10 items, after which it starts a new row. I have done this successfully, however, every row in every column displays the same number. For example. My output would be:

1 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2 2 2 2 2

When it should be appearing as something along the lines of:

1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20

Here is the following method I am using to print the table:

public static void printTable(int[] emirps) {
    for (int i = 0; i < 100; i++) {
        for (int j = 0; j < 10; j++) {
            // After 10 go to a new line
            System.out.printf("%d\t", emirps[i]);
        }
        System.out.println("");
    }
}

If anyone can help me pinpoint where I have goofed I’d greatly appreciate it.

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  1. Editorial Team
    Editorial Team
    2026-06-02T04:58:43+00:00Added an answer on June 2, 2026 at 4:58 am

    You are printing the same emirps[i] each time through the inner loop. There are a couple of ways around this. Here’s one:

    public static void printTable(int[] emirps) {
        for (int i = 0; i < 100; i += 10) {
            for (int j = 0; j < 10; j++) {
                // After 10 go to a new line
                System.out.printf("%d\t", emirps[i + j]);
            }
            System.out.println();
        }
    }
    

    Here’s another (not very elegant):

    public static void printTable(int[] emirps) {
        for (int i = 0; i < 100; ++i) {
            System.out.printf("%d\t", emirps[i]);
            if (i % 10 == 9) {
                System.out.println();
            }
        }
    }
    
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