Question

I was wondering if there is a way to let type members reference each other. I would like to write the following program like this:

type IDieRoller =
    abstract RollDn : int -> int
    abstract RollD6 : int
    abstract RollD66 : int

type DieRoller() =
    let randomizer = new Random()

    interface IDieRoller with
        member this.RollDn max = randomizer.Next(max)
        member this.RollD6 = randomizer.Next(6)
        member this.RollD66 = (RollD6 * 10) + RollD6

But, this.RollD66 is unable to see this.RollD6. I can sort of see why, but it seems most functional languages have a way of letting functions know that they exist ahead of time so that this or similar syntax is possible.

Instead I’ve had to do the following, which isn’t much more code, but it seems that the former would look more elegant than the latter, especially if there are more cases like that.

type DieRoller() =
    let randomizer = new Random()

    let rollD6 = randomizer.Next(6)

    interface IDieRoller with
        member this.RollDn max = randomizer.Next(max)
        member this.RollD6 = rollD6
        member this.RollD66 = (rollD6 * 10) + rollD6

Any tips? Thanks!

Answer 1

If the class is nothing more than an interface implementation, you can use an object expression. I prefer this, when possible, for its conciseness.

namespace MyNamespace

type IDieRoller =
    abstract RollDn : int -> int
    abstract RollD6 : int
    abstract RollD66 : int

module DieRoller =

    open System

    [<CompiledName("Create")>]
    let makeDieRoller() =
        let randomizer = new Random()
        { new IDieRoller with
            member this.RollDn max = randomizer.Next max
            member this.RollD6 = randomizer.Next 6
            member this.RollD66 = this.RollD6 * 10 + this.RollD6 }

F#

open MyNamespace.DieRoller
let dieRoller = makeDieRoller()

C#

using MyNamespace;
var dieRoller = DieRoller.Create();