Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 940767
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T22:00:34+00:00 2026-05-15T22:00:34+00:00

I was wondering if this $c = mysql_num_rows(mysql_query(select * from action_6_weekly where code=’$code’)); is

  • 0

I was wondering if this

$c = mysql_num_rows(mysql_query("select * from action_6_weekly where code='$code'"));

is considered valid PHP?

Or do I need to do the following?

$r = mysql_query("select * from action_6_weekly where code='$code'");
$c = mysql_num_rows($r);

this is what i am actually doing:

if($entry == '9')
    $c = mysql_num_rows(mysql_query("select * from action_6_5pts where code='$code'")) or die ('MYSQL ERROR: '.mysql_error().' in '.__FILE__.' on '.__LINE__.'.');
elseif($entry == 'a')
    $c = mysql_num_rows(mysql_query("select * from action_6_10pts where code='$code'")) or die ('MYSQL ERROR: '.mysql_error().' in '.__FILE__.' on '.__LINE__.'.');
else
    $c = mysql_num_rows(mysql_query("select * from action_6_weekly where code='$code'")) or die ('MYSQL ERROR: '.mysql_error().' in '.__FILE__.' on '.__LINE__.'.');

if($c > 0) 
    $waiting_for_reply = false;
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T22:00:35+00:00Added an answer on May 15, 2026 at 10:00 pm

    It is generally better to do it on separate lines and assign it a variable.

    This way you can work with the result easier. But to get a count of rows, if that is all you are looking for, this would be better and more efficient:

    $r = mysql_query("select count(id) from action_6_weekly where code='$code'");
    $c = mysql_result($r, 0, 0);

    Where the id is the unique identifier field to count.

    EDIT:
    Given that you do not care how many rows there are, just that it exists:

    $r = mysql_query("select code from action_6_weekly where code='$code' LIMIT 1");
    if (mysql_num_rows($r) > 0) {
        // echo it exists!
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 545k
  • Answers 545k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • added an answer Well, start off by thinking of which bits of data… May 17, 2026 at 9:17 am
  • added an answer For this task it is a good idea to use… May 17, 2026 at 9:15 am
  • added an answer This is exactly how the Skyhook database (built into many… May 17, 2026 at 9:15 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.