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Home/ Questions/Q 6331633
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T18:06:27+00:00 2026-05-24T18:06:27+00:00

I was wondering, my Scandir() function works on a php $_GET variable, so the

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I was wondering, my Scandir() function works on a php $_GET variable, so the variable returns the folder, but I’m having a problem because I’m not sure how to echo out an error if there is a problem with with directory.

this is the error I am getting:

Warning: scandir(users/ro/f) [function.scandir]: failed to open dir: No such file or directory in C:\xampp\htdocs\OSO\desktop\main_content\file.php on line 31

This is my code

$folder = $_GET['file_folder'];
$directory = "users/$username/$folder";
if (scandir($directory, 0)) {
    unset($documents[0], $documents[1]);
    $documents = scandir($directory, 0);

    // for each loop
} else {
    echo "No such directory";
}

Cheers in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T18:06:28+00:00Added an answer on May 24, 2026 at 6:06 pm

    I would first check whether $directory exists using is_dir() before calling scandir():

    if (is_dir($directory)) {
        $filenames = scandir($directory, 0);
        // do something
    } else {
        echo "No such directory";
    }
    
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