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Home/ Questions/Q 4065356
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T15:58:21+00:00 2026-05-20T15:58:21+00:00

I was wondering what the difference (of any kind) is when using a vector

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I was wondering what the difference (of any kind) is when using a vector of vectors to represent a 2D matrix or make a class like:

template < class T > 
class Matrix2D {
public:
    Matrix2D( unsigned m, unsigned n ) : m( m ), n( n ), x( m * n ) {} ;
    Matrix2D( const Matrix2D<T> &matrix ) : m( matrix.m ), n( matrix.n) x( matrix.x ) {} ;
    Matrix2D& operator= ( const Matrix2D<T> &matrix ) ;
    T& operator ()( unsigned i, unsigned j ) ;
    void resize( int nx, int ny ) ;
private:
    unsigned m, n ;
    std::vector< T > x ;         
} ;


template <class T>
T& Matrix2D<T>::operator ()( unsigned i, unsigned j ) {
    return x[ j + n * i ] ;
}

template <class T>
Matrix2D<T>& Matrix2D<T>::operator= ( const Matrix2D<T> &matrix ) {
    m = matrix.m ;
    n = matrix.n ;
    x = matrix.x ;
    return *this ;
}

template <class T>
void Matrix2D<T>::resize( int nx, int ny ) {
    m = nx ;
    n = ny ;
    x.resize( nx * ny ) ;
}

Edit: Ignore the resize method, as Erik pointed out it would not keep original data place. I only added for a specific task where I didn’t mind. The basic class is just the ctor and the () operator.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T15:58:22+00:00Added an answer on May 20, 2026 at 3:58 pm
    • – .resize() will not keep existing data in the original positions.
    • – Syntax differences, operator() vs operator[]
    • – No iterators, and no using e.g. std:: algorithms
    • + Better locality, backing vector has contiguous memory
    • + More understandable syntax for initialization
    • + Guarantees that the array isn’t jagged

    In short, the class is fine and likely better for specialized purposes, but it’s not doing too well on generic-purpose.

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