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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T12:51:29+00:00 2026-05-20T12:51:29+00:00

I was wondering whether for most examples it is more ‘pythonic’ to use lambda

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I was wondering whether for most examples it is more ‘pythonic’ to use lambda or the partial function?

For example, I might want to apply imap on some list, like add 3 to every element using:

imap(lambda x : x + 3, my_list)

Or to use partial:

imap(partial(operator.add, 3), my_list)

I realize in this example a loop could probably accomplish it easier, but I’m thinking about more non-trivial examples.

In Haskell, I would easily choose partial application in the above example, but I’m not sure for Python. To me, the lambda seems the the better choice, but I don’t know what the prevailing choice is for most python programmers.

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  1. Editorial Team
    Editorial Team
    2026-05-20T12:51:30+00:00Added an answer on May 20, 2026 at 12:51 pm

    To be truly equivalent to imap, use a generator expression:

    (x + 3 for x in mylist)
    

    Like imap, this doesn’t immediately construct an entire new list, but instead computes elements of the resulting sequence on-demand (and is thus much more efficient than a list comprehension if you’re chaining the result into another iteration).

    If you’re curious about where partial would be a better option than lambda in the real world, it tends to be when you’re dealing with variable numbers of arguments:

    >>> from functools import partial
    >>> def a(*args):
    ...     return sum(args)
    ... 
    >>> b = partial(a, 2, 3)
    >>> b(6, 7, 8)
    26
    

    The equivalent version using lambda would be…

    >>> b = lambda *args: a(2, 3, *args)
    >>> b(6, 7, 8)
    26
    

    which is slightly less concise – but lambda does give you the option of out-of-order application, which partial does not:

    >>> def a(x, y, z):
    ...    return x + y - z
    ...
    >>> b = lambda m, n: a(m, 1, n)
    >>> b(2, 5)
    -2
    
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