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Editorial Team
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Asked: 2026-05-29T16:03:27+00:00

I was working on some data parsing code while I came across the following.

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I was working on some data parsing code while I came across the following.

$line = "100 something is amazingly cool";
$key = 100;

var_dump($line == $key);

Well most of us would expect the dump to produce a false, but to my surprise the dump was a true!

I do understand that in PHP there is type conversion like that:

$x = 5 + "10 is a cool number"; // as documented on PHP manual
var_dump($x); // int(15) as documented.

But why does a comparison like how I mentioned in the first example converts my string to integer instead of converting the integer to string.

I do understand that you can do a === strict-comparison to my example, but I just want to know:

  • Is there any part of the PHP documentation mentioning on this behaviour?
  • Can anyone give an explanation why is happening in PHP?
  • How can programmers prevent such problem?
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1 Answer

  1. Editorial Team

    If I recal correcly PHP ‘casts’ the two variables to lowest possible type.
    They call it type juggling.

    try: var_dump("something" == 0);
    for example, that’ll give you true . . had that bite me once before.

    More info: http://php.net/manual/en/language.operators.comparison.php

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