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Home/ Questions/Q 3311928
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T21:56:03+00:00 2026-05-17T21:56:03+00:00

I wasn’t clear how to correctly name this question. Case 1 Assume that I

  • 0

I wasn’t clear how to correctly name this question.

Case 1

Assume that I have the following directory structure.

foo
|
+- bar/__init__.py
|
+- bar.py

If I have

from foo import bar

How do I know which bar (bar.py or bar/__init__.py) is being imported? Is there any easy way to automatically detect this from occurring?

Case 2

foo
|
+- foo.py
|
+- other.py

If other.py has the line

import foo

How do I know which foo (foo or foo.foo) is being imported? Again, is tehre any easy way to automatically detect this from occurring?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T21:56:03+00:00Added an answer on May 17, 2026 at 9:56 pm

    TLDR; a package takes precedence over a module of the same name if they are in the same directory.

    From the docs:

    “When a module named spam is imported, the interpreter searches for a file named spam.py in the current directory, and then in the list of directories specified by the environment variable PYTHONPATH. This has the same syntax as the shell variable PATH, that is, a list of directory names.”

    This is a bit misleading because the interpreter will also look for a package called spam (a directory called spam containing an __init__.py file). Since the directory entries are sorted before searching, packages take precedence over modules with the same name if they are in the same directory because spam comes before spam.py.

    Note that “current directory” is relative to the main script path (the one where __name__ == '__main__' is True). So if you are at /home/billg calling /foo/bar.py, “current directory” refers to /foo.

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