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Home/ Questions/Q 8241879
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T20:58:43+00:00 2026-06-07T20:58:43+00:00

I will need to create array of integer arrays like [[0,1,2],[4,4,5,7]…[4,5]] . The size

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I will need to create array of integer arrays like [[0,1,2],[4,4,5,7]...[4,5]]. The size of internal arrays changeable. Max number of internal arrays is 2^26. So what do you recommend for the fastest way for updating this array.
When I use list=[[]] * 2^26 initialization is very fast but update is very slow. Instead I use

list=[] , for i in range(2**26): list.append.([]) .

Now initialization is slow, update is fast. For example, for 16777216 internal array and 0.213827311993 avarage number of elements on each array for 2^26-element array it takes 1.67728900909 sec. It is good but I will work much bigger datas, hence I need the best way. Initialization time is not important.
Thank you.

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  1. Editorial Team
    Editorial Team
    2026-06-07T20:58:46+00:00Added an answer on June 7, 2026 at 8:58 pm

    What you ask is quite of a problem. Different data structures have different properties. In general, if you need quick access, do not use lists! They have linear access time, which means, the more you put in them, the longer it will take in average to access an element.

    You could perhaps use numpy? That library has matrices that can be accessed quite fast, and can be reshaped on the fly. However, if you want to add or delete rows, it will might be a bit slow because it generally reallocates (thus copies) the entire data. So it is a trade off.

    If you are gonna have so many internal arrays of different sizes, perhaps you could have a dictionary that contains the internal arrays. I think if it is indexed by integers it will be much faster than a list. Then, the internal arrays could be created with numpy.

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