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Editorial Team
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Asked: 2026-06-03T17:24:17+00:00

I will work with third party API. They accept a date pattern like: 2012-02-15T17:34:37.937-0600

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I will work with third party API. They accept a date pattern like:

2012-02-15T17:34:37.937-0600

I know the pattern should be match like

yyyy-MM-ddTHH:mm:ss.s

But I am not sure how to represent the last “-0600” timezone? I think the standard timezone is “-06:00”, anyone knows how to get rid of the “:” in the date pattern?

Thanks.

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1 Answer

  1. Editorial Team

    maybe you want “Z” ?

    see http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html:

    • ‘z’ gives you “Pacific Standard Time; PST; GMT-08:00”
    • ‘Z’ gives you “-0800”

    This code:

    final SimpleDateFormat f = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SZ");

    produces:

    2012-05-11T12:21:57.598+1000

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