Question

I wish to initialise a vector using an array of std::strings.

I have the following solution, but wondered if there’s a more elegant way of doing this?

std::string str[] = { "one", "two", "three", "four" };
vector< std::string > vec;
vec = vector< std::string >( str, str + ( sizeof ( str ) /  sizeof ( std::string ) ) );

I could, of course, make this more readable by defining the size as follows:

int size =  ( sizeof ( str ) /  sizeof ( std::string ) );

and replacing the vector initialisation with:

vec = vector< std::string >( str, str + size );

But this still feels a little “inelegant”.

Answer 1

Well the intermediate step isn’t needed:

std::string str[] = { "one", "two", "three", "four" };
vector< std::string > vec( str, str + ( sizeof ( str ) /  sizeof ( std::string ) ) );

In C++11 you’d be able to put the brace initialization in the constructor using the initializer list constructor.