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Home/ Questions/Q 4274094
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T07:48:03+00:00 2026-05-21T07:48:03+00:00

I wish to replace values in each div class with my ajax result but

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I wish to replace values in each div class with my ajax result but i cannot seem to append my table result to the individual div class during the loop. I know somehow the $(this).append(table) is placed wrongly because it is not outside of the ajax request. How can i modify this to get the effect i wanted?

my script is as such:

$('.developer_badgesarea').each(function(){
    // get the div class value to perform ajax
    var player_id = $(this).html();
    var table;

    // if condition to conduct ajax
    if(player_id != 'None'){

        $.ajax({
            // ajax stuff here
            success: function(result){
                //table created here
                $(this).append(table);
            }
        });
    }
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T07:48:04+00:00Added an answer on May 21, 2026 at 7:48 am

    Issue is your “this” reference inside the ajax success function. It references the callback function, instead of the dom element you are intending it to be referenced.

    $('.developer_badgesarea').each(function(){
        // element reference to your div, that you'll access inside your ajax call
        var elm = $(this);
        // get the div class value to perform ajax
        var player_id = elm.html(); 
        var table;

    // if condition to conduct ajax
    if(player_id != 'None'){
    
        $.ajax({
            // ajax stuff here
            success: function(result){
                //table created here
                elm.append(table);
            }
        });
    }
    

    });

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