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Home/ Questions/Q 517101
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:47:58+00:00 2026-05-13T07:47:58+00:00

I wish to retrieve the source of a website, that is dynamically generated upon

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I wish to retrieve the source of a website, that is dynamically generated upon clicking a link. The link itself is as below:

<a onclick="function(); return false" href="#">Link</a>

This stops me from directly querying for a URL that would allow me to get the dynamically generated website (urllib/2).

How would one retrieve the source of the website, which was generated with the above function (in HTML) via python? Is there a method to bypass the return false" href="#"? Or the onclick entirely, and get the actual URL?

If there is another way to generate the website from the abstract link above, so that one can get it from urllib in python, please refer me to it.


EDIT:

I generalized the code seen above – however I’ve been told that one has to reverse engineer the specific javascript to be able to use it.

Link to .js – http://a.quizlet.com/j/english/create_setku80j8.js

Link to site with link:

<a onclick="importText(); return false" href="#">Bulk-import data</a>

Actual URL of site: http://quizlet.com/create_set/

Beautified JS of relevant .js above: http://pastie.org/737042

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:47:59+00:00Added an answer on May 13, 2026 at 7:47 am

    I don’t immediately see any content-generation or link-following code in that script; all importText does is toggle whether a few divs are shown.

    If you want to study the calls the webapp makes to do a particular action, in order to reproduce them from a bot, you’re probably best off looking at the HTTP requests (form submissions and AJAX calls) that the browser makes whilst performing that action. You can use Firebug’s ‘Net’ panel to study this for Firefox, or Fiddler for IE.

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