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Home/ Questions/Q 1074533
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Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T21:08:27+00:00 2026-05-16T21:08:27+00:00

I wish to use a function with an arbitrary number of arguments to edit

  • 0

I wish to use a function with an arbitrary number of arguments to edit an array. The code I have so far is:

 function setProperty()
 {
  $numargs = func_num_args();
  $arglist = func_get_args();
  $toedit = array();
  for ($i = 0; $i < $numargs-1; $i++)
  {
   $toedit[] = $arglist[$i];
   }
   $array[] = $arglist[$numargs-1];
 }

The idea of the code being I can do the following:

setProperty('array', '2nd-depth', '3rd', 'value1');
setProperty('array', 'something', 'x', 'value2');
setProperty('Another value','value3');

Resulting in the following array:

Array
(
    [array] => Array
        (
            [2nd-depth] => Array
                (
                    [3rd] => value1
                )

            [something] => Array
                (
                    [x] => value2
                )

        )

    [Another Value] => value3
)

The issue I believe is with the line:

$toedit[] = $arglist[$i];

What does this line need to be to achieve the required functionality?

Cheers,

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:08:27+00:00Added an answer on May 16, 2026 at 9:08 pm

    You need to walk the path to the destination before storing the new value. You can do this with a reference:

    function setProperty() {
        $numargs = func_num_args();
        if ($numargs < 2) return false; // not enough arguments
        $arglist = func_get_args();
    
        // reference for array walk    
        $ar = &$array;
        // walk the array to the destination
        for ($i=0; $i<$numargs-1; $i++) {
            $key = $arglist[$i];
            // create array if not already existing
            if (!isset($ar[$key])) $ar[$key] = array();
            // update array reference
            $ar = &$ar[$key];
        }
    
        // add value
        $ar = $arglist[$numargs-1];
    }
    

    But the question where this $array should be stored still remains.

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