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Home/ Questions/Q 7165297
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T14:12:59+00:00 2026-05-28T14:12:59+00:00

I wonder how C++ behaves in this case: char variable = 127; variable++; In

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I wonder how C++ behaves in this case:

char variable = 127;
variable++;

In this case, variable now equals to -128. However did the increment operator wrapped the value to its lower bound or did an overflow occurred?

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  1. Editorial Team
    Editorial Team
    2026-05-28T14:13:00+00:00Added an answer on May 28, 2026 at 2:13 pm

    An overflow occured and results in undefined behavior.

    Section 5.5:

    Ifduring the evaluation of an expression, the result is not
    mathematically defined or not in the range of representable values
    for its type
    , the behavior is undefined […]

    The standard goes on to note that integer overflows are, in most implementations, ignored. But this doesn’t represent a guarantee.

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