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Home/ Questions/Q 7697839
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T22:06:12+00:00 2026-05-31T22:06:12+00:00

I wonder how is this possible in groovy to start an array from the

  • 0

I wonder how is this possible in groovy to start an array from the n element.

Look at the snippet :

static void main(args){

    if (args.length < 2){
        println "Not enough parameters"
        return;
    }

    def tools = new BoTools(args[0])
    def action = args[1]

    tools."$action"(*args)

    System.exit(1)

}

As you see am doing here a dynamic method invocation. The first 2 arguments are taken as some config and method name , the others I would like to use as method paramerts.
So how can I do something like this :

tools."$action"(*(args+2))

Edited : If not possilbe in native groovy Java syntax will do it :

def newArgs = Arrays.copyOfRange(args,2,args.length);
tools."$action"(*newArgs)
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  1. Editorial Team
    Editorial Team
    2026-05-31T22:06:13+00:00Added an answer on May 31, 2026 at 10:06 pm

    To remove items from the beginning of the args you can use the drop() method. The original args list is not changed:

    tools."$action"(*args.drop(2))
    

    Other option, like you are trying is to access from N element:

    tools."$action"(*args[2..-1])
    
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