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Editorial Team
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Asked: 2026-05-14T04:06:49+00:00

I wonder if someone can help shed some light on this: I drop a

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I wonder if someone can help shed some light on this:

I drop a cookie if a user arrives to the site with a specific key/value in query string. i.e.: http://www.somesite.com?key=hmm01

The cookie code exists at top of the template before <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML ) :

<?php
header("Content-Type: text/html; charset=utf-8");
ob_start();
if (isset($_GET['key'])) {
setcookie("cookname", $_GET['key'], time()+2592000); /* Expires in a month */
}
ob_end_flush();
?>

On the same page though within the : I have the following php code that sniffs the cookie and outputs some text:

`

switch ($cookievalue)
{
case hmm01:
echo “abc”;
break;
case hmm02:
echo “def”;
break;
case hmm03:
echo “ghi”;
break;
default:
echo “hello”;
}
?>`

— Problem is when the user first arrives the sniffer script doesn’t detect the cookie and outputs the default text: hello
Only when user refreshes page or navigates to a different page does the sniffer detect the cookie.

Any ideas on how to drop the cookie and output the correct text without a page refresh?

Many thanks.

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1 Answer

  1. Editorial Team

    Simply check $_GET for the first time:

    if(isset($_GET['key'])) { $cookievalue = $_GET['key']; }
if(isset($_COOKIE['cookname'])) { $cookievalue = $_COOKIE['cookname']; }

switch ($cookievalue) { case hmm01: echo "abc"; break; case hmm02: echo "def"; break; case hmm03: echo "ghi"; break; default: echo "hello"; } ?>
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