I wonder whether someone can help me please.
I’ve found this tutorial to create a drop down menu using mySQL table data, which, in turn returns a list of results on the page.
Following this tutorial I’ve put together the tables in my database and the required scripts which are shown below:
Search Form
<html>
<head>
<script type="text/javascript">
function ajaxFunction()
{
//document.writeln(val)
var httpxml;
try
{
// Firefox, Opera 8.0+, Safari
httpxml=new XMLHttpRequest();
}
catch (e)
{
// Internet Explorer
try
{
httpxml=new ActiveXObject("Msxml2.XMLHTTP");
}
catch (e)
{
try
{
httpxml=new ActiveXObject("Microsoft.XMLHTTP");
}
catch (e)
{
alert("Your browser does not support AJAX!");
return false;
}
}
}
function stateChanged(){
if(httpxml.readyState==4){
var myObject = eval('(' + httpxml.responseText + ')');
//var myObject = httpxml.responseText;
//document.getElementById("display").innerHTML=myObject;
var msg=myObject.value[0].message;
if(msg.length > 0){document.getElementById("msg").innerHTML=msg;}
else{document.getElementById("msg").style.display='none';}
var str="<table width='50%' bgcolor='#ffffff' align=center><tr><th>ID</th><th>Name</th></tr>";
var color="#f1f1f1";
for(i=0;i<myObject.data.length;i++)
{
if((i%2)==0){color="#ffffff";}
else{color="#f1f1f1";}
str = str + "<tr bgcolor="+color+"><td>" + myObject.data[i].subcat_id + " </td><td>"+ myObject.data[i].subcat_name + "</a></td></tr>"
}
str = str + "</table>" ;
document.getElementById("display").innerHTML=str;
}
}
var url="subcat2.php";
var cat_id=document.myForm.cat_id.value;
url=url+"?cat_id="+cat_id;
url=url+"&kid="+Math.random();
//alert(url)
httpxml.onreadystatechange=stateChanged;
httpxml.open("GET",url,true);
httpxml.send(null);
// document.getElementById("display").innerHTML="Please Wait....";
document.getElementById("msg").style.background='#f1f1f1';
document.getElementById("msg").innerHTML="Please Wait ... ";
document.getElementById("msg").style.display='inline';
}
</script>
<?php
require "z_db.php";
echo "</head><body onload="ajaxFunction()";>";
echo "<center><table border='0' width='100%' cellspacing='0' cellpadding='0' > <tr bgcolor='#ffffcc'><form name=myForm method='post' onSubmit="ajaxFunction(this.form); return false">
<td align='center' colspan=2><font face='verdana, arial, helvetica' size='2' ><b> Select a Category</b> </font></td></tr>";
echo "<tr>";
echo "<td align='center'>";
$query="SELECT * FROM plus2_cat order by cat_name";
$result=mysql_query($query);
echo mysql_error();
echo "<select name=cat_id onChange="ajaxFunction()"><option value=0>Show All</option>";
while($nt=mysql_fetch_array($result)){
echo "<option value=$nt[cat_id]>$nt[cat_name]</option>";
}
echo "</select>";
echo "</font></td>";
echo "</tr></form>";
echo "</table>";
?>
<div id=msg style="position:absolute; z-index:1; left: 1100px; top: 0px;" >This is message area</div>
<div id="display"><b>Records will be displayed here</b></div>
</body>
</html>
subcat2.php
<?php
////// Your Database Details here /////////
require ("z_db.php");
//Your database details here
//////////////////////////// Main Code sarts ///////////////
$cat_id=$_GET['cat_id'];
//$cat_id=11;
if(!is_numeric($cat_id)){
$message.="Data Error |";
exit;
}
//$message.=" :Status = $status";
if($cat_id>0){
$q=mysql_query("select subcat_id, subcat_name from plus2_subcat where cat_id=$cat_id order by subcat_name");
}else{
$q=mysql_query("select subcat_id, subcat_name from plus2_subcat order by subcat_name ");
$cat_id=0;
}
//$message .=" Cat_id=$cat_id ";
$message .= mysql_error();
$str= "{ "data" : [ ";
while($nt=mysql_fetch_array($q)){
$str=$str."{"subcat_id" : "$nt[subcat_id]", "subcat_name" : "$nt[subcat_name]"},";
//$str=$str."{"myclass" : "$nt[class]"},";
}
$str=substr($str,0,(strLen($str)-1));
$message=$message. " Records displayed";
$str=$str."],"value" : [{"cat_id" : $cat_id,"message" : "$message"}]}";
//echo json_encode($str);
echo $str;
?>
z_db.php
<?php
mysql_connect("host", "user", "password")or
die(mysql_error());
mysql_select_db("database");
?>
The problem I ahve is that when I try and run this, I receive the following error:
Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /homepages/2/d333603417/htdocs/development/catsearch.php on line 91 which is this line in the search form: echo "</head><body onload="ajaxFunction()";>";.
I must admit I’ve guessed as to the structure of the’z_db.php’ file should look like because this is not shown so perhaps this is the problem.
I just wondered wether someone could perhaps take a look at this please and let me know where I’ve gone wrong.
Try:
You cannot nest single/double quotes.