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I wonder why in the following code, d is not being consed into x.
Any hints are much appreciated.
(defun it (x)
(setq f '(a b c))
(dolist (d f)
(cons d x))
(print x))
Thank you!
I don’t know a lot about LISP, but here’s a few things I think I know that might help you:
(cons d x) doesn’t put d “into” x; it creates a new value that consists of d, followed by the contents of x. If x is a list, then (cons d x) will also be a list.
(cons d x) doesn’t change anything; it creates a value, but if you don’t capture that value, it gets discarded again. In particular, that expression doesn’t change x.