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Home/ Questions/Q 6559237
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:17:55+00:00 2026-05-25T13:17:55+00:00

I work in a python shell and some weeks ago I have defined a

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I work in a python shell and some weeks ago I have defined a variable which refers to a very important list. The shell stays always open, but I have forgotten this name. How to get a list of all global names I have ever defined?

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  1. Editorial Team
    Editorial Team
    2026-05-25T13:17:55+00:00Added an answer on May 25, 2026 at 1:17 pm

    All of the globals or just the user-defined ones?

    >>> globals()
    {'__builtins__': <module '__builtin__' (built-in)>, '__name__': '__main__', '__doc__': None, '__package__': None}
    >>> x=2
    >>> globals()
    {'__builtins__': <module '__builtin__' (built-in)>, '__name__': '__main__', 'x': 2, '__doc__': None, '__package__': None}
    

    To get the things you have defined yourself, it appears that you can filter out from this list all key-value pairs whose keys do not match the regex "__.*?__$".

    UPDATE

    Here is a better answer:

    $ python
    Python 2.7.1 (r271:86832, Jun  5 2011, 15:52:25) 
    [GCC 4.2.1 (Apple Inc. build 5659)] on darwin
    Type "help", "copyright", "credits" or "license" for more information.
    >>> x = 3
    >>> import re
    >>> [name for name in dir() if not re.match(r'__.*?__$', name)]
    ['re', 'x']
    

    Here I’ve excluded the special names beginning and ending with two underscores, so if you used them yourself they will not show. The $ at the end of the regex to prevent accepting __abc__1. Also I switched to dir() which gets symbols in the current scope, not necessarily the global one, but it seems cleaner. It doesn’t add the leading list comprehension variable like globals() does.

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