Question

I worked on a JSP code that is runnning on a Tomcat5.5 server in windows system .

I had to copy all the JSP code to a linux system and when I did the same I got an error stating below.

 javax.servlet.ServletException: c:\tmp is not a directory
 Readcsv.init(Readcsv.java:36)
 org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117)
 org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:174)
 org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875)


org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665)
 org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528)
 org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:81)
 org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:689)
 java.lang.Thread.run(Thread.java:636)

I modified a java code in the windows system without that c:\tmp directory and restarted the tomcat server and the tool worked fine.

When I replaced the modified java code of windows to the linux system, I still get the same error.

Note: Am accessing the linux server from windows using the url http://192.168.0.85:8080/CNA/uploadcsv.jspwhere 85 is the system number of linux.

Is there anything like tomcat has to be restarted for the linux version too? If so how to do the same?

UPDATE

This is where I have used the c:\tmp location in my code.

public class Readcsv extends HttpServlet {
private static final String TMP_DIR_PATH = "c:\tmp";
private File tmpDir;
private static final String DESTINATION_DIR_PATH ="/files";
private File destinationDir;

public void init(ServletConfig config) throws ServletException {
    super.init(config);
    tmpDir = new File(TMP_DIR_PATH);
    if(!tmpDir.isDirectory()) {
        throw new ServletException(TMP_DIR_PATH + " is not a directory");
    }
    String realPath = getServletContext().getRealPath(DESTINATION_DIR_PATH);
    destinationDir = new File(realPath);
    if(!destinationDir.isDirectory()) {
        throw new ServletException(DESTINATION_DIR_PATH+" is not a directory");
    }

}

How can I find the replacement for the temp path? The destination path works fine.
I exactly copied the code from this example

Answer 1

Don’t hardcode disk file system paths in your code. That’s only portability and maintainability trouble.

In case of temporary files, rather make use of File#createTempFile().

File tempfile = File.createTempFile("name", ".ext");

It will automatically create the temp file at the right location, regardless of the environment. You can however also obtain the tmp dir root location by System.getProperty("java.io.tmpdir");.

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In case of resources which are to be read by your application, just put them in the runtime classpath or add their path to the runtime classpath. Then you can just obtain them from the classpath by getResource() and getResourceAsStream() methods on Class or ClassLoader.

InputStream input = getClass().getResourceAsStream("file.properties");

If you really need to have a fixed path outside the classpath, then rather define it in a properties file so that you at least have any control over the path from outside the application (so, without the need to change the code everytime).

String path = properties.getProperty("my.file.path");