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Home/ Questions/Q 897825
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Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T14:56:42+00:00 2026-05-15T14:56:42+00:00

I would be happy to access any element of multi-dimensional hash-array by a shorter

  • 0

I would be happy to access any element of multi-dimensional hash-array by a shorter expression

h = {a: {b: 'c'}}

# default way
p h[:a][:b] # => "c"

# a nicer way
p h[:a,:b] # => "c"

# nice assignment
h[:a,:b] = 1
p h # => {:a=>{:b=>1}}

I realize that in this way one eliminates the possibility to have a hash key being an array.

{[:a,:b] => "c"}

Since it is quite rare situation, I would prefer to reduce number of [] in my expressions.

How can one achieve this?


Update

Ok, I wasn’t clear. The problem is that I have tried to make custom [] and []= methods myself, but failed. Could you show me how such functionality can be implemented?

Multi-dimensional arrays

If you are looking for something similar for arrays, have a look on narray gem http://narray.rubyforge.org/

>> a = NArray.int(5,5)
=> NArrayint5,5: 
[ [ 0, 0, 0, 0, 0 ], 
  [ 0, 0, 0, 0, 0 ], 
  [ 0, 0, 0, 0, 0 ], 
  [ 0, 0, 0, 0, 0 ], 
  [ 0, 0, 0, 0, 0 ] ]
>> a[1,2]
=> 0
>> a[1,2]=1
=> 1
>> a
=> NArrayint5,5: 
[ [ 0, 0, 0, 0, 0 ], 
  [ 0, 0, 0, 0, 0 ], 
  [ 0, 1, 0, 0, 0 ], 
  [ 0, 0, 0, 0, 0 ], 
  [ 0, 0, 0, 0, 0 ] ]
>> a[1,0..4]=1
=> 1
>> a
=> NArrayint5,5: 
[ [ 0, 1, 0, 0, 0 ], 
  [ 0, 1, 0, 0, 0 ], 
  [ 0, 1, 0, 0, 0 ], 
  [ 0, 1, 0, 0, 0 ], 
  [ 0, 1, 0, 0, 0 ] ]
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T14:56:43+00:00Added an answer on May 15, 2026 at 2:56 pm

    I have fixed my code, so now it works

    class AutoHash < Hash
      def initialize *args
        super
        @update, @update_index = args[0][:update], args[0][:update_key] unless 
    args.empty?
      end
    
        def [] key,*args
          if args.count > 0
            self[key][*args]
          else
            if self.has_key? key
              super key
            else
              AutoHash.new :update => self, :update_key => key
            end
          end
        end
    
        def []= *args
          v = args.pop
          k = args.shift
          if args.count > 0
            self[k][*args]= v
          else
            @update[@update_index] = self if @update and @update_index
            super k,v
          end
        end
    end
    

    Examples

    a = AutoHash.new
    a[:a][:b][:c] = 123
    a[:a,:b,:c] = 321
    p a # => {:a=>{:b=>{:c=>321}}}
    

    If such definition is too confusing, then one could name the method differently (e.g. #path instead of redifining [])

    h[:a][:b][:c] = 123
    p h.path(:a,:b,:c) # => 123
    
    h.path(:a,:b,:c)= 321
    p h #=> {:a=>{:b=>{:c=>321}}}
    
    mypath = [:a,:b,:c]
    p h.path(mypath) #=> 321
    
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