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Home/ Questions/Q 9136067
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T08:54:16+00:00 2026-06-17T08:54:16+00:00

I would like my command line program to take file parameters in the form:

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I would like my command line program to take file parameters in the form:

-out:%MyDocuments%\dummy.xps

and having %MyDocuments% automatically replaced with:

Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments)

I know it’s an easy to write function, but I guess it should be already done somewhere, so I don’t want to re-invent the wheel.

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  1. Editorial Team
    Editorial Team
    2026-06-17T08:54:17+00:00Added an answer on June 17, 2026 at 8:54 am

    You can use Environment.ExpandEnvironmentVariables(variable);

    The input doesn’t need to be a single variable, it can be a ‘query’, like your path, with variables embedded and it will expand all those it finds/recognises. This is shown in the snippet at the link given:

    String query = "My system drive is %SystemDrive% and my system root is %SystemRoot%";
    str = Environment.ExpandEnvironmentVariables(query);
    Console.WriteLine("ExpandEnvironmentVariables: {0}  {1}", Environment.NewLine, str);
    
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