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Home/ Questions/Q 7661791
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T13:38:43+00:00 2026-05-31T13:38:43+00:00

i would like to append an item into list_b only if it is one

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i would like to append an item into list_b only if it is one above '5H' which is '6H'

list_a = ('2A','4A','8H','6H')
list_b = ['5H']

list_a.pop() gives a '6H'
therefore if i append the '6H' it should be able to be added to list_b since its just one above '5H'.

i tried to compare the first values but it gives an error because the 1 in the code below is an int and list_b[-1][0] is a str.

if list_b[-1][0] + 1 != list_a.pop()[0]:
    print('Error')

Therefore i cannot use list_b[-1][0] + 1

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T13:38:44+00:00Added an answer on May 31, 2026 at 1:38 pm

    Presuming that list_a really is a list, not a tuple, otherwise list_a.pop() won’t work …

    You need to do TWO things:

    (1) convert the first characters to int so that you can compare them properly
    (2) check that the second characters are the same … from your problem description, it would appear that '6G' and '6I' (amongst many others) are not OK

    b_value = list_b[-1]
    a_value = list_a.pop()
    
    ok = int(b_value[0]) + 1 == int(a_value[0]) and b_value[1] == a_value[1]
    
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