Question

I would like to ask for assistance on how to convert the code below to PDO type especially the mysql_fetch_array. I can make it work properly using this code but I want to convert to PDO.

 <?php

    $query = "SELECT * from name";
    $result = mysql_query($query);

    $cols = 6;
    echo "<table>";
    do {
        echo "<tr>";
        for ($i = 1; $i <= $cols; $i++) {

            $row = mysql_fetch_array($result);
            if ($row) {
                $name = $row['fname'];
    ?>
                    <td>
                    <table>
                    <tr valign="top">
                    <td>
                    <?php echo '<input type="checkbox" name="name[]" id="name[]" value="' . $name . '"/>' . $name . "\n"; ?>
                    </td>
                    <td width="30">&nbsp;</td>   
                    </tr>
                    </table>
                    </td>
    <?php
            } else {
                echo "<td>&nbsp;</td>";
            }
        }
    } while ($row);
    echo "</table>";
    ?>

Answer 1

First off, you can read more at http://php.net/pdo.

$dsn = 'mysql:dbname=testdb;host=127.0.0.1';
$user = 'dbuser';
$password = 'dbpass';

try {
    $dbh = new PDO($dsn, $user, $password);
} catch (PDOException $e) {
    echo 'Connection failed: ' . $e->getMessage();
}

$query = "SELECT * from name";

$stmt = $dbh->prepare($query);

$stmt->execute();

// Start your html col/row setup

// Loop through your cols

$row = $stmt->fetch(PDO::FETCH_ASSOC);

For your example it’s not necessary to ‘prepare’ however it is a good practice when you start passing values to your query.