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Home/ Questions/Q 6730719
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:26:33+00:00 2026-05-26T10:26:33+00:00

I would like to build a rule like this one in my Makefile: log:

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I would like to build a rule like this one in my Makefile:

log: test_A test_B
    ./test_A >> $@
    ./test_B >> $@

but test_A and test_B are part of a $(TESTS) variable.

So, is it possible to do an action (here: call the program) for each prerequisite in GNU/make?

Note: How do I make a makefile rule execute its prerequisites? does not completely solve this problem, as the target log is required (make log).

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:26:33+00:00Added an answer on May 26, 2026 at 10:26 am

    Essentially you want to loop over the prerequisites. The obvious way to do this is to punt to the shell:

    log: test_A test_B
            for f in $^; do ./$$f; done
    

    Or you could write the loop as a GNU Make foreach loop, though you have to be careful that the commands that result from the body of the loop appear on separate lines (via define) or are terminated with a shell terminator (i.e., a semi-colon, which is easier):

    log: test_A test_B
            $(foreach f,$^,./$(f);)
    

    Finally, in this case you could write it more succinctly and more obscurely as a pattern substitution on each item to be looped over:

    log: test_A test_B
            $(patsubst %,./%;,$^)
    

    (I’m sure you can add the output redirection and $(TESTS) variable as appropriate.)

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