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Home/ Questions/Q 3216492
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T15:18:03+00:00 2026-05-17T15:18:03+00:00

I would like to construct a search query that groups the records by their

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I would like to construct a search query that groups the records by their ‘tag’ attribute, and finds a certain number of records for each tag group. My ‘place’ table is as follows:

| ID | name | geom | rating_av | tag |

There are four different tags that a place can be assigned – “city”, “food”, “hotel” and “attraction”. I would like my search to be able to return the top five records for each tag group, ordered by rating_av, with an additional geometric constraint. I can query each tag at a time with the following (which seems to work fine):

Place.find(:all, :limit => 5, :conditions => ["geom && ? and tag = ?", Polygon.from_coordinates([[[xMinLng, yMinLat], [xMinLng, yMaxLat], [xMaxLng, yMaxLat], [xMaxLng, yMinLat], [xMinLng, yMinLat]]], 4326), "food"])

However, I’d like to be able to retrieve the first five records for each tag in a single query. What is the best way to construct such a query? Should I think about adding the ‘tag’ column as an index to aid searching? I’ve tried adding :group => 'tag' to the query, but I’m not too sure how to use it correctly, as I got the following error back:

ActiveRecord::StatementInvalid (PGError: ERROR:  column "places.id" must appear in the GROUP BY clause or be used in an aggregate function

Any help is greatly appreciated, thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T15:18:04+00:00Added an answer on May 17, 2026 at 3:18 pm
    Place.all(
      :joins => "INNER JOIN (
          SELECT     a.id, COUNT(*) AS ranknum
          FROM       places AS a
          INNER JOIN places AS b ON (a.tag = b.tag) AND (a.rating_av <= b.rating_av)
          GROUP BY   a.id
          HAVING COUNT(*) <= 5
        ) AS d ON (places.id = d.id)",
    :order => "places.tag, d.ranknum"
    )
    

    For a detailed explanation of this query look at this article.

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