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Home/ Questions/Q 897375
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T14:52:42+00:00 2026-05-15T14:52:42+00:00

i would like to create a flexible logger class. I want it to be

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i would like to create a flexible logger class. I want it to be able to output data to a file or to standard output. Also, i want to use streams. The class should look something like:

class Logger
{
private:
   std::ostream m_out; // or ofstream, iostream? i don't know
public:

   void useFile( std::string fname);
   void useStdOut();

   void log( symbol_id si, int val );
   void log( symbol_id si, std::string str );
   //etc..
};

The symbol_id is an enum and defines the formatting. What i want to achieve is to be able to easily switch from standart output to a file and vice versa (this is the purpose of the use* methods). Preferably by just using m_out and simply writing m_out << "something"; without any checks whether i want to write to a file or stdout.

I know there are many ways how to get around this (using if's to test if i want to write to a file or stdout, the “C way” (using FILE* and fprintf)) and so on, but i’m sure there must be a way how to achieve this with C++ streams in a nice way. But i can’t seem to find the way how to do it. Can somebody help me please?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T14:52:43+00:00Added an answer on May 15, 2026 at 2:52 pm

    The way I’ve attacked this problem before is to make Logger an abstract base class and create separate FileLogger and OutStreamLogger classes. Then create a CompositeLogger object that implements the Logger interface, which just outputs all loggers:

    CompositeLogger compLogger;
    compLogger.Add(new FileLogger("output.txt"));
    compLogger.Add(new StreamLogger(std::cout));
    ...
    compLogger.log(...);
    

    If you don’t need this level of flexibility and want to keep all this in a single class you could make the m_Out variable a pointer to std::ostream and add an extra flag to keep track of whether you need to delete it on cleanup:

    private:
      std::ostream*   m_out;
      bool            m_OwnsStream;
    
    Logger() {
       m_Out=&std::cout; // defaults to stdout
       m_OwnsStream=false;
    }
    void useFile(std::string filename) {
      m_Out=new std::ofstream(filename);
      m_OwnsStream=true;
    }
    ~Logger() {
      if (m_OwnStream) 
        delete m_Out; 
    }
    

    Obviously you’d need some more checks in useFile and useStdOut to prevent memory leaks.

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