Question

I would like to create a forward-function that terminates the caller-function.
Currently I’m using “exit” in the callee-function to achieve this.

function caller (){
    if($condition){
        forward();
    }
    //code that is not executet if $condition is true
}

//current solution
function forward(){
    //do something
    exit;
}

I would like to omit the return-statement after calling the forward-function.

I guess there is no other way except throwing an exception?

Thanks for your help.

Answer 1

There are several ways:

1) Enclosing the code after if info else branch

2) As you mentioned, throwing an exception

3) or plainly doing:

function caller (){
    if($condition){
        forward();
        return; // you return nothing (void, in PHP's case that would be NULL, I believe)
    }
    //code that is not executet if $condition is true
}