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Home/ Questions/Q 7030067
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:37:16+00:00 2026-05-28T00:37:16+00:00

I would like to create an XML file like this: <?xml version=1.0 encoding=UTF-8?> <text>

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I would like to create an XML file like this:

<?xml version="1.0" encoding="UTF-8"?>
<text>
<languages>
    <language id =1>English</language>
    <language1 id=2>Slovenian</language1>
</languages>
<strings>
    <line id=1>
        <string lid=1>camera</string>
        <string lid=2>kamera</string1>
    </line>
    <line id=2>
        <string lid=1>lens</string>
        <string1 lid=2>leka</string1>
    </line>
</strings>
</text>

I am trying with the following code in C# (Windows Forms Application):

        XmlDocument xmldoc = new XmlDocument();
        XmlDeclaration xmldec = xmldoc.CreateXmlDeclaration("1.0", null, null);
        xmldoc.AppendChild(xmldec);
        XmlElement root = xmldoc.CreateElement("text");
        xmldoc.AppendChild(root);
        XmlElement lang = xmldoc.CreateElement("languages");
        XmlElement languages = xmldoc.CreateElement("language");
        languages.SetAttribute("id", "1");
        languages.InnerText = "English";
        lang.PrependChild(languages);
        languages.SetAttribute("id", "2");
        languages.InnerText = "Slovenian";
        lang.PrependChild(languages);
        XmlElement lines = xmldoc.CreateElement("strings");
        XmlElement line = xmldoc.CreateElement("line");
        XmlElement lineinner = xmldoc.CreateElement("string");
        line.SetAttribute("id", "1");
        lineinner.SetAttribute("lid", "1");
        lineinner.InnerText = "some english text";
        line.AppendChild(lineinner);
        line.SetAttribute("id", "1");
        lineinner.SetAttribute("lid", "2");
        lineinner.InnerText = "some slovenian text";
        line.AppendChild(lineinner);
        lines.AppendChild(line);
        root.AppendChild(lang);
        root.AppendChild(lines);
        Metodi.SerializeXMLToXML(xmldoc);

And i end up with the following result:

<?xml version="1.0" encoding="UTF-8"?>
<text>
    <languages>
        <language id="2">Slovenian</language>
    </languages>
    <strings>
        <line id="2">
            <string lid="2">some slovenian text</string>
        </line>
    </strings>
</text>

After every next AppendChild() replaces the previous is there any way to achieve this??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:37:17+00:00Added an answer on May 28, 2026 at 12:37 am

    Re-initialize it every time is one solution:

    XmlDocument xmldoc = new XmlDocument();
    XmlDeclaration xmldec = xmldoc.CreateXmlDeclaration("1.0", null, null);
    xmldoc.AppendChild(xmldec);
    XmlElement root = xmldoc.CreateElement("text");
    xmldoc.AppendChild(root);
    XmlElement lang = xmldoc.CreateElement("languages");
    XmlElement languages = xmldoc.CreateElement("language");
    languages.SetAttribute("id", "1");
    languages.InnerText = "English";
    lang.PrependChild(languages);
    languages = xmldoc.CreateElement("language");
    languages.SetAttribute("id", "2");
    languages.InnerText = "Slovenian";
    lang.PrependChild(languages);
    XmlElement lines = xmldoc.CreateElement("strings");
    XmlElement line = xmldoc.CreateElement("line");
    XmlElement lineinner = xmldoc.CreateElement("string");
    line.SetAttribute("id", "1");
    lineinner.SetAttribute("lid", "1");
    lineinner.InnerText = "some english text";
    line.AppendChild(lineinner);
    line = xmldoc.CreateElement("string");
    line.SetAttribute("id", "1");
    lineinner.SetAttribute("lid", "2");
    lineinner.InnerText = "some slovenian text";
    line.AppendChild(lineinner);
    lines.AppendChild(line);
    root.AppendChild(lang);
    root.AppendChild(lines);
    Metodi.SerializeXMLToXML(xmldoc);
    

    Nodes can only have one parent, hence your problem. A nicer way to resolve this, though, might be to use XML literals. It has come to my attention that C# does not support XML literals. This doesn’t change the fact that you can write this in a nicer way using XML serialization or loops and such.

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