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Home/ Questions/Q 6469267
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T05:58:16+00:00 2026-05-25T05:58:16+00:00

I would like to create arrays of void pointers. # include <stdio.h> # include

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I would like to create arrays of void pointers.

# include <stdio.h>
# include <stdlib.h>
# include <unistd.h>

int main(){

void * A[3];
void * D[3];
void * F[2];
void * G[4];
void * H[4];
void * J[3];
void * K[5];
void * L[4];
void * M[5];


A={D, H, K};
D ={A, G, H};
F ={K, L};
G={D, H, J, M};
H={A, G, L, M};
J={G, L, M};
K={A, F, H, L, M};
L={F, J, K, M};
M={G, H, J, K, L};
return 0;
}

The problem is the code won’t compile it says: “expected expression before { token”

What is wrong?
I am using these pointers because their value doesn’t matter I just want them to point to each other. For example M has to point to G, H, J, K and L.

Thank you very much for any help or advice,

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  1. Editorial Team
    Editorial Team
    2026-05-25T05:58:17+00:00Added an answer on May 25, 2026 at 5:58 am

    You have to do it on the same line if you want to use that notation. In your case you would have to do

    A[0] = D;
    A[1] = H;
    A[2] = K;
    

    and so on because you need to add void * to symbols that havent been resolved at that point yet.

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