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Home/ Questions/Q 1043689
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:42:30+00:00 2026-05-16T15:42:30+00:00

I would like to define some template member methods inside a template class like

  • 0

I would like to define some template member methods inside a template class like so:

template <typename T>
class CallSometing {
public:
    void call (T tObj);  // 1st 

    template <typename A>
    void call (T tObj, A aObj); // 2nd 

    template <typename A>
    template <typename B>
void call (T tObj, A aObj, B bObj); // 3rd

};


template <typename T> void
CallSometing<T>::call (T tObj) {
    std::cout << tObj << ", " << std::endl;
}

template <typename T>
template <typename A> void
CallSometing<T>::call (T tObj, A aObj) {
    std::cout << tObj << ", " << aObj << std::endl;
}


template <typename T>
template <typename A>
template <typename B> void
CallSometing<T>::call (T tObj, A aObj, B bObj) {
    std::cout << tObj << ", " << aObj << ", " << bObj << ", " << std::endl;
}

But when instantializing the template class, there is an error concerning the three-argument menthod definition:

CallSometing<int> caller;

caller.call(12);  // OK
caller.call(12, 13.0); // OK
caller.call (12, 13.0, std::string("lalala!")); // NOK - complains "error: too many template-parameter-lists"

Could you please point what I am doing wrong? Why the (2nd) method is OK but the (3rd) causes a compile time error?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:42:31+00:00Added an answer on May 16, 2026 at 3:42 pm

    Please read a C++ template tutorial on how to give a template multiple parameters. Instead of

    template<typename A> template<typename B> void f(A a, B b);
    

    The way it is done is

    template<typename A, typename B> void f(A a, B b);
    

    Multiple template clauses represent multiple levels of templates (class template -> member template).

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