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Home/ Questions/Q 6961919
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T15:35:35+00:00 2026-05-27T15:35:35+00:00

I would like to define the following two functions: void Map<T>(Func<T, string> mapper); T

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I would like to define the following two functions:

void Map<T>(Func<T, string> mapper);

T Call<T>(string value);

Map needs to store the function that turns a string into a result of type T so that when the “Call” function is called with a type T and a string the appropriate function can be looked up and called.

I was thinking that map could store the function in a dictionary of type Dictionary<Type, Func<object, string>> and then Call could do the casting to the appropriate type but I’m unable to get that to work. Does anyone know how to achieve this?

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  1. Editorial Team
    Editorial Team
    2026-05-27T15:35:35+00:00Added an answer on May 27, 2026 at 3:35 pm

    The first type argument of Func is the input, the second the output: Func<in T, out TResult> — so you need Func<string, T>.

    (The MSDN reference here uses Func<string, string> a fair bit which is annoying.)

    Also, the dictionary can’t use the type argument T as that’s different for each element in the dictionary. Rather, use the superclass of Func<T, TResult> which is Delegate.

    This should work:

        Dictionary<Type, Delegate> dictionary = new Dictionary<Type, Delegate>();
    
        public void Map<T>(Func<string, T> mapper)
        {
            dictionary[typeof(T)] = mapper;
        }
    
        public T Call<T>(string value)
        {
            var func = dictionary[typeof(T)] as Func<string, T>;
            return func.Invoke(value);
        }
    
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