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Home/ Questions/Q 7718615
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T03:12:31+00:00 2026-06-01T03:12:31+00:00

I would like to disallow double forward slashes (//) in my regular expression (and

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I would like to disallow double forward slashes (//) in my regular expression (and thus allow single /), but my solutions doesn’t work.

There also has to be NO / at the beginning and ending of a string (this work!):

/^[^/][a-z0-9-/]+[^/]$$/

this allows for example example///example// but NOT/dzkoadokzd///zdkoazaz

Now I want to disallow multiple “/” after each other.
I’ve tried this but it doesn’t work (I’m new to regular expressions):

/^[^/]([a-z0-9-]+[/]{1})+[^/]$$/
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  1. Editorial Team
    Editorial Team
    2026-06-01T03:12:32+00:00Added an answer on June 1, 2026 at 3:12 am

    / is a meta character in regex. You need to escape it with a backslash (\/)

    /^[^\/]([a-z0-9-]+[\/]{1})+[^\/]$/
    
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