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Editorial Team
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Asked: 2026-06-17T09:24:55+00:00

I would like to do bash -c ‘<some smart bash script>’ that would output

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I would like to do bash -c '<some smart bash script>' that would output the actual string passed to -c.

In other words, if SCRIPT is set to that smart script, bash -c "$SCRIPT" should yield what’s in $SCRIPT.

Is that possible? If yes, how?

Thanks

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1 Answer

  1. Editorial Team

    See man bash

    5.2 Bash Variables
    …
    BASH_EXECUTION_STRING
    The command argument to the -c invocation option.

    If you try

    bash -c 'echo $BASH_EXECUTION_STRING'

    it will give you

    echo $BASH_EXECUTION_STRING

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