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Asked: May 10, 20262026-05-10T23:37:37+00:00 2026-05-10T23:37:37+00:00

I would like to do the equivalent off this (ruby code) in python for

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I would like to do the equivalent off this (ruby code) in python for a Django project I am working on. I want to make a filmstrip image of X number of images in a folder.

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  1. 2026-05-10T23:37:38+00:00Added an answer on May 10, 2026 at 11:37 pm

    Here is a function that wraps the contact sheet function S.Lott mentioned.

    #!/usr/bin/env python  import os, os.path from contactsheet import make_contact_sheet  def make_film_strip(fnames,                    (photow,photoh),                    (marl,mart,marr,marb),                    padding):     return make_contact_sheet(fnames,                               (1, len(fnames)),                               (photow,photoh),                               (marl,mart,marr,marb),                               padding) 

    It is assuming the recipe is saved as contactsheet.py. Usage is:

    fstrip = filmstrip.make_film_strip(filmstrip.fnames, (120, 120), (0,0,0,0), 0) fstrip.save('/path/to/file.format') 

    Tested.

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