Question

I would like to do the following: Given a container with perspective and an inner element with a translateZ value I’d like to “pull it up” with translateY in order to visually touch the top of the surrounding container: http://jsfiddle.net/8R4ym/129/

Is there some kind of formula that, given the perspective value of a container, the width and height of an element and it’s Z-translation I can get to that kind of “top” calculation? I have been playing around with it but I can’t seem to find some rules for it, as it seems that those are all variables.

Thanks for any help.

Answer 1

Yes!

There’s actually quite a simple formula for finding the offset – the 3d Projection article on Wikipedia has a diagram and the formula.

The formula is bx = ax * bz / az where:

• ax is the original distance from the transform origin point
• az is the perspective + the negative translateZ
• bz is the perspective

and this will give you:

• bx – the new distance from the transform origin point

So, you need to know:

• bz : the perspective (eg: 1000px)
• ax : the offset from the transform origin point, eg: if the origin point is 50% then this needs to be the element’s top relative to the center of the parent element (parent.height/2 + element.top) — let’s say -500px
• z : the element’s translateZ (eg: -600px)
• az is then bz + z * -1, in this case: 1000 + (-600 * -1) = 1600

so the formula is: -500 * 1000 / 1600 = -312.5

The element is offset vertically -312.5px from the origin, whereas originally it was offset -500px, the difference between the two number is what you’ll need to add to the old top value to get the equivalent new value.

This formula also works for the Y axis.

I put together a quick example here: http://jsfiddle.net/trolleymusic/xYRgx/