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Home/ Questions/Q 6939645
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:38:55+00:00 2026-05-27T12:38:55+00:00

I would like to export (or to keep) the subtags which are with the

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I would like to export (or to keep) the subtags which are with the defined attribute in XML. As I don’t know the name of this process, I can’t find any relevant information about it on the net. And since it’s hard to explain, I decided to put an examples for my issue.

Let’s say, I have this XML file:

<results>
    <result idSite="1">
        <row>
            <label>category</label>
            <visits>2</visits>
            <idsubdatatable>5</idsubdatatable>
            <subtable>
                <row>
                    <label>uncategorized</label>
                    <visits>2</visits>
                    <idsubdatatable>6</idsubdatatable>
                    <subtable>
                        <row>
                            <label>/index</label>
                            <visits>2</visits>
                            <url>http://mysite1.com/category/uncategorized/</url>
                        </row>
                    </subtable>
                </row>
            </subtable>
        </row>
        <row>
            <label>about</label>
            <visits>1</visits>
            <idsubdatatable>7</idsubdatatable>
            <subtable>
                <row>
                    <label>/index</label>
                    <visits>1</visits>
                    <url>http://mysite1.com/about/</url>
                </row>
            </subtable>
        </row>
    </result>
    <result idSite="2">
        <row>
            <label>/calendar</label>
            <visitors>1</visitors>
            <url>http://mysite2.com/calendar</url>
        </row>
    </result>
</results>

And I have to parse the results and keep only the rows which are with a <url> attribute. Like this:

xml parsing

After parsing I have to combine these rows in a new XML file, and the final result must be like this:

<result>
<row>
    <label>/index</label>
    <visits>2</visits>
    <url>http://mysite1.com/category/uncategorized/</url>
</row>
<row>
    <label>/index</label>
    <visits>1</visits>
    <url>http://mysite1.com/about/</url>
</row>
<row>
    <label>/calendar</label>
    <visitors>1</visitors>
    <url>http://mysite2.com/calendar</url>
</row>
</result>

Generally I want to do this process in PHP but it maybe in other languages too.
So, if you have any idea to solve this problem, please comment.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:38:56+00:00Added an answer on May 27, 2026 at 12:38 pm

    I would use an xpath query to find all url nodes inside row nodes. Then, just append the parent node of each url element you find to a new DomDocument like so:

    $xml = '...';
    $dom = new DomDocument();
    $dom->preserveWhiteSpace = FALSE;
    $dom->loadXML($xml);
    
    $new_dom = new DomDocument();
    $result = $new_dom->createElement('result');
    $new_dom->appendChild($result);
    
    $xpath = new DOMXPath($dom);
    $rows = $xpath->query('//row/url');
    
    for ($i=0;$i<$rows->length;$i++) {
      $node = $new_dom->importNode($rows->item($i)->parentNode, TRUE);
      $result->appendChild($node);
    }
    
    $new_dom->formatOutput = TRUE;
    echo $new_dom->saveXML();
    
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