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Home/ Questions/Q 880825
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T12:09:41+00:00 2026-05-15T12:09:41+00:00

I would like to extract a zip folder to a location and to replace

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I would like to extract a zip folder to a location and to replace all files and folders except a few, how can I do this?

I currently do the following.

$backup = realpath('./backup/backup.zip');

$zip = new ZipArchive();

if ($zip->open("$backup", ZIPARCHIVE::OVERWRITE) !== TRUE) {

    die ('Could not open archive');

}

$zip->extractTo('minus/');

$zip->close();

How can I put conditions in for what files and folders should NOT be replaced? It would be great if some sort of loop could be used.

Thanks all for any help

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  1. Editorial Team
    Editorial Team
    2026-05-15T12:09:42+00:00Added an answer on May 15, 2026 at 12:09 pm

    You could do something like this, I tested it and it works for me:

    // make a list of all the files in the archive
    $entries = array();
    for ($idx = 0; $idx < $zip->numFiles; $idx++) {
        $entries[] = $zip->getNameIndex($idx);
    }
    
    // remove $entries for the files you don't want to overwrite
    
    // only extract the remaining $entries
    $zip->extractTo('minus/', $entries);
    

    This solution is based on the numFiles property and the getNameIndex method, and it works even when the archive is structured into subfolders (the entries will look like /folder/subfolder/file.ext).
    Also, the extractTo method takes a second optional paramer that holds the list of files to be extracted.

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